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y=4/3*3.14^3
We move all terms to the left:
y-(4/3*3.14^3)=0
We get rid of parentheses
y-4/3*3.14^3=0
We multiply all the terms by the denominator
y*3*3.14^3-4=0
Wy multiply elements
9y^2*3-4=0
Wy multiply elements
27y^2-4=0
a = 27; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·27·(-4)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*27}=\frac{0-12\sqrt{3}}{54} =-\frac{12\sqrt{3}}{54} =-\frac{2\sqrt{3}}{9} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*27}=\frac{0+12\sqrt{3}}{54} =\frac{12\sqrt{3}}{54} =\frac{2\sqrt{3}}{9} $
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